Janelia Fluor 525
Janelia Fluor® 525 (Ex-Max 525 nm/Em-Max 549 nm)
Janelia Fluor® 525 was developed at the Janelia Campus of the Howard Hughes Medical Institute but is commercialized by other vendors. The Janelia Fluor®s family is unique in that the fluorophores are cell-permeable and are available in photoactivatable forms. These fluorophores were developed for super-resolution microscopy (STED, PALM and STORM) and live-cell microscopy in the HaloTag and SNAP-tag versions. Janelia Fluor® 525 has an excitation peak at 525 nm and an emission peak at 549 nm.
Excitation & emission spectra
Key facts
- Excitation maximum
- 525 nm
- Emission maximum
- 549 nm
- Optimal laser line
- 488/532
- Optimal filter
- 525/50
- Relative brightness
- 2 of 5
- Extinction coefficient
- 122000
- Quantum yield
- 0.91
Janelia Fluor 525 has an excitation maximum at 525 nm and an emission maximum at 549 nm, a Stokes shift of 24 nm. Its extinction coefficient is 122000 M⁻¹cm⁻¹. It is optimally excited by the 488/532 laser line.
Frequently asked questions
- What is Janelia Fluor 525?
- Janelia Fluor® 525 was developed at the Janelia Campus of the Howard Hughes Medical Institute but is commercialized by other vendors. The Janelia Fluor®s family is unique in that the fluorophores are cell-permeable and are available in photoactivatable forms. These fluorophores were developed for super-resolution microscopy (STED, PALM and STORM) and live-cell microscopy in the HaloTag and SNAP-tag versions. Janelia Fluor® 525 has an excitation peak at 525 nm and an emission peak at 549 nm.
- What laser excites Janelia Fluor 525?
- Janelia Fluor 525 is optimally excited by the 488/532 laser line. Its excitation maximum is 525 nm.
- What filter should I use to detect Janelia Fluor 525?
- A 525/50 filter captures the peak of the Janelia Fluor 525 emission near 549 nm with minimal spillover.
- How bright is Janelia Fluor 525?
- Janelia Fluor 525 has a relative brightness of 2 out of 5 (quantum yield 0.91).